The Challenge: Create Accessible Resources
I work at a state university in the Commonwealth of Virginia. [Note that this document represents my personal experiences and opinions and is not meant to imply any endorsement by my university or the state—I'm just stating that for context.] Last year, the US federal government published final rulings on the ADA requirements for accessibility for web content on government websites, which includes state universities.
As a mathematician, I am used to posting documents in PDF form. Sometimes these are scans of handwritten solutions. Or they could be documents prepared using LaTeX. It is my understanding that both of these are problematic.
In this post, I want to explore dealing with handwritten solutions. The traditional work is just images. This would not meet the Perceivable or Understandable requirements. Is it possible for an instructor to start with their handwritten work and use current tools to convert it to an electronic representation that meets compliance?
Step 1: Create an example
Step 2: Try AI
ChatGPT
Convert this image to a markdown file, using latex math formulas for the math that appears in the document.
1. Solve \( 3x^2 - 5x - 2 = 0 \)Look for factors of \( (3)(-2) = -6 \) that add to -5.\[-6 + 1 = -5 \quad \text{and} \quad (-6)(1) = -6\]Rewrite \( 3x^2 - 5x - 2 = 3x^2 - 6x + 1x - 2 \) and factor by grouping:\[(3x^2 - 6x) + (x - 2) = 0 \\3x(x - 2) + (x - 2) = 0 \\(3x + 1)(x - 2) = 0\]Because this is now in the factored form \( AB = 0 \), we can solve each factor as an independent equation:\[3x + 1 = 0 \quad \Rightarrow \quad 3x = -1 \quad \Rightarrow \quad x = -\frac{1}{3}\]\[x - 2 = 0 \quad \Rightarrow \quad x = 2\]The solutions are \( x = -\frac{1}{3} \) and \( x = 2 \).
Copilot
The attached image is a scan of a solution to a math exercise. Convert the image to a markdown file using LaTeX representations for each formula that appears in the document.
1. Solve \(3x^2 - 5x - 2 = 0\)Look for factors of \((3)(-2) = -6\) that add to \(-5\):- \(6 + (-1) = 5\)- \((-6)(1) = -6\)Rewrite \(3x^2 - 5x - 2 = 3x^2 - 6x + 1x - 2\) and factor by grouping:\[ (3x^2 - 6x) + (1x - 2) = 0 \]\[ (3x(x-2)) + (1(x-2)) = 0 \]\[ (3x+1)( x-2 )=0 \]Because this is now in the factored form \(AB=0\), we can solve each factor as an independent equation:\[\begin{cases}3x+1=0 \\x-2=0\end{cases}\]Solving these equations:\[\begin{cases}x=-\frac{1}{3} \\x=2\end{cases}\]The solutions are \( x=-\frac{1}{3} \) and \( x=2 \).
Conclusions
Step 3: Convert to PreTeXt
<exercise><title>Solve a Quadratic Equation by Factoring</title><statement><p>Solve the equation <m>3x^2 - 5x - 2 = 0</m>.</p></statement><solution><p>Look for factors of <m>(3)(-2) = -6</m> that add to <m>-5</m>.</p><ul><li><m>-6 + 1 = -5</m></li><li><m>(-6)(1) = -6</m></li></ul><p>Rewrite <m>3x^2 - 5x - 2</m> as <m>3x^2 - 6x + x - 2</m>, and factor by grouping:</p><md><mrow>(3x^2 - 6x) + (x - 2) = 0</mrow><mrow>3x(x - 2) + (x - 2) = 0</mrow><mrow>(3x + 1)(x - 2) = 0</mrow></md><p>Because this is now in the factored form <m>AB = 0</m>, we can solve each factor as an independent equation:</p><ul><li><me>3x + 1 = 0</me><me>3x = -1</me><me>x = -\frac{1}{3}</me></li><li><me>x - 2 = 0</me><me>x = 2</me></li></ul><p>The solutions are <m>x = -\frac{1}{3}</m> and <m>x = 2</m>.</p></solution></exercise>
<handout xml:id="quadratic-factoring-example" xmlns="http://pretextbook.org"><title>Solving a Quadratic Equation by Factoring</title><introduction><p>This example demonstrates how to solve a quadratic equation using factoring and grouping techniques.</p></introduction><exercise><title>Solve a Quadratic Equation by Factoring</title><statement><p>Solve the equation <m>3x^2 - 5x - 2 = 0</m>.</p></statement><solution><p>Look for factors of <m>(3)(-2) = -6</m> that add to <m>-5</m>.</p><ul><li><m>-6 + 1 = -5</m></li><li><m>(-6)(1) = -6</m></li></ul><p>Rewrite <m>3x^2 - 5x - 2</m> as <m>3x^2 - 6x + x - 2</m>, and factor by grouping:</p><md><mrow>(3x^2 - 6x) + (x - 2) = 0</mrow><mrow>3x(x - 2) + (x - 2) = 0</mrow><mrow>(3x + 1)(x - 2) = 0</mrow></md><p>Because this is now in the factored form <m>AB = 0</m>, we can solve each factor as an independent equation:</p><ul><li><me>3x + 1 = 0</me><me>3x = -1</me><me>x = -\frac{1}{3}</me></li><li><me>x - 2 = 0</me><me>x = 2</me></li></ul><p>The solutions are <m>x = -\frac{1}{3}</m> and <m>x = 2</m>.</p></solution></exercise></handout>